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-0.01x^2+350x-1750=0
a = -0.01; b = 350; c = -1750;
Δ = b2-4ac
Δ = 3502-4·(-0.01)·(-1750)
Δ = 122430
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-\sqrt{122430}}{2*-0.01}=\frac{-350-\sqrt{122430}}{-0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+\sqrt{122430}}{2*-0.01}=\frac{-350+\sqrt{122430}}{-0.02} $
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